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4.9x^2-80x-102=0
a = 4.9; b = -80; c = -102;
Δ = b2-4ac
Δ = -802-4·4.9·(-102)
Δ = 8399.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-\sqrt{8399.2}}{2*4.9}=\frac{80-\sqrt{8399.2}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+\sqrt{8399.2}}{2*4.9}=\frac{80+\sqrt{8399.2}}{9.8} $
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